How Ruby method lookup works?

 When we call a method on an object, Ruby looks for the implementation of that method. 

 It looks in the following places and uses the first implementation it finds:

1. Methods from the object's singleton class (an unnamed class that only exists for that object)
2. Methods from prepended modules (Ruby 2.0+ feature)
3. Methods from the object's class
4. Methods from included modules
5. Methods from the class hierarchy (superclass and its ancestors)

class Superclass

  def monk

    puts "rormonk Superclass"

  end 

end

module IncludedModule

  def monk

    puts "rormonk Included module"

    super

  end

  

end

module PrependedModule

  def monk

    puts "rormonk Prepended module"

    super

  end

  

end

module SingletonModule

  def monk

    puts "rormonk Singleton class"

    super

  end

end

class Klass < Superclass

  include IncludedModule

  prepend PrependedModule

  def monk

    puts "rormonk Klass"

    super

  end

  

end

kl = Klass.new kl.extend(SingletonModule) 

kl.monk

Singleton class

Prepended module

Klass

Included module

Superclass

So when I saw first I extend the class and then call the method than obvious it will call that but later I realize if I will not extend that how would I call that 😅

there will be some people like me who could think superclass is mention in every method due to that it is printing like this 😊 so this is for the super is used to maintain the chain so if you will not put super it will not call the other method and it will just return the first method print value.

✌